It says zero or even more event of whitespace characters, accompanied by a comma after which you can accompanied by zero or more prevalence of whitespace characters. Even so x.replaceAll("\s+", ""); will likely be much more efficient method of trimming Areas (if string can have a number of contiguous spaces) https://sergiojctiw.blogerus.com/53810497/little-known-facts-about-mantra-mushroom-chocolate